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Topic 2.1

Change in Arithmetic and Geometric Sequences

Two new streaming channels launch in the same month. Ridge starts with 1,200 subscribers and gains 300 more every month. Nova starts much smaller, with only 256 subscribers, but every month its audience is 1.5 times what it was the month before. Ridge begins more than four and a half times bigger. Which channel is bigger after a year?

15 MIN READ10 IDEAS33 PROBLEMS3 flashcards

Read this first

30 sec

  1. 01

    A sequence has inputs 0, 1, 2, 3, …, so its graph is separate dots.

  2. 02

    Arithmetic: add dd every step. Geometric: multiply by rr every step.

Most people bet on Ridge. By the end of this note you will see why that bet loses, and why. Unit 2 is about the difference between two kinds of change: adding the same amount again and again, and multiplying by the same factor again and again. Sequences are the simplest place to see that difference, so that is where we begin.

Remember from 1.3: a linear function has a constant rate of change. In this note you will meet its step-by-step cousin (the arithmetic sequence) and a new kind of pattern whose change is not constant but proportional (the geometric sequence).

01

What Is a Sequence?

CONCEPT

A Sequence Is a Function on Whole Numbers

A sequence is an ordered list of numbers. Each number is a term. We name the terms a0a_{0}, a1a_{1}, a2a_{2}, … (read “a sub zero”, “a sub one”, …), and the small number nn in ana_{n} (the index) tells you the position. The index is a LABEL for the position, not a multiplication: a3a_{3} is the term in position 3, not a times 3.

Think of a sequence as a function: the input is the index n=0n = 0, 1, 2, 3, …, and the output is the term ana_{n}.

Only whole-number inputs exist. There is a month 3 and a month 4, but no month 3.5. The outputs, though, can be any real number: negative, fractional, or decimal.

For example, the rule tn=n2+2t_{n} = n^{2} + 2 gives t0=2t_{0} = 2, t1=3t_{1} = 3, and t4=18t_{4} = 18. Asking for t2.5t_{2.5} makes no sense, because 2.5 is not a position in the list. That is why the graph of a sequence is a set of separate dots. We never join them into a line or a curve.

KEY RULE

A sequence has inputs 0, 1, 2, 3, …, so its graph is separate dots.

This course focuses on two special kinds of sequences. Our two channels are one of each.

02

Arithmetic Sequences: Add the Same Amount

Here is Ridge's subscriber count at the end of each month (n=0n = 0 is launch month):

n (month)012345
ana_{n} (subscribers)120015001800210024002700
change—+300+300+300+300+300

CONCEPT

Common Difference dd

A sequence is arithmetic when every step adds the same number dd. That number is the common difference.

Because the change over every step of the same length is constant, an arithmetic sequence has a constant rate of change, exactly like a linear function. For Ridge, d=300d = 300 subscribers per month.

Why does the formula look the way it does? To get from a0a_{0} to ana_{n} you take nn steps, and each step adds dd:

an=a0+(d+d+⋯+d)=a0+d n(n copies of d)a_n = a_0 + (d + d + \cdots + d) = a_0 + d\,n \qquad (n\text{ copies of }d)

So the explicit rule, the rule that jumps straight to any term, is

an=a0+d na_n = a_0 + d\,n

For Ridge, a0=1200a_{0} = 1200 and d=300d = 300, so an=1200+300na_{n} = 1200 + 300n.

Now you can answer questions without listing every month. After one year, a12=1200+300(12)=4,800a_{12} = 1200 + 300(12) = 4,800 subscribers. After two years, a24=8,400a_{24} = 8,400.

03

Geometric Sequences: Multiply by the Same Factor

Now look at Nova. This time the changes are not constant; they keep getting bigger. But divide each term by the one before it, and the answer is 1.5 every time.

n (month)012345
gng_{n} (subscribers)25638457686412961944
change—+128+192+288+432+648
ratio—×1.5×1.5×1.5×1.5×1.5

CONCEPT

Common Ratio rr

A sequence is geometric when every step multiplies by the same nonzero number rr. That number is the common ratio.

Put another way, over every step of the same length the output changes by the same proportion. For Nova, r=1.5r = 1.5 means each month's audience is 150% of the previous month's, a 50% increase every month.

The formula comes from counting steps again. To get from g0g_{0} to gng_{n} you multiply by rr a total of nn times:

gn=g0⋅(r⋅r⋯r)=g0⋅rn(n copies of r)g_n = g_0 \cdot (r \cdot r \cdots r) = g_0 \cdot r^{n} \qquad (n\text{ copies of }r)

So the explicit rule is

gn=g0⋅rng_n = g_0 \cdot r^{n}

For Nova, g0=256g_{0} = 256 and r=1.5r = 1.5, so gn=256(1.5)ng_{n} = 256(1.5)^{n}.

Figure

Left: every rise is +300. Right: every rise is 1.5 times the one before it, so the rises keep growing.

KEY RULE

Arithmetic: ADD dd every step. Geometric: MULTIPLY by rr every step.

04

Which Channel Wins?

Let's continue both tables past month 5:

n (month)5678
Ridge ana_{n}2700300033003600
Nova gng_{n}1944291643746561

Figure

Ridge is ahead through month 6. Nova passes it in month 7 and pulls away fast.

Ridge's gain is stuck at 300 every month. Nova's gain is 1.5 times its previous gain, so it grows every month: +128, +192, +288, and then +432 from month 3 to month 4. From that step on, Nova gains more than 300 each month and closes the gap, until it passes Ridge in month 7 and pulls away.

This is the big idea of Unit 2. Repeated multiplication by a factor greater than 1 eventually beats repeated addition, no matter how big a head start the adding side gets. In 2.2 you will see the same contest between linear and exponential functions.

05

Arithmetic, Geometric, or Neither?

CONCEPT

The Two Tests

Subtract consecutive terms. If every difference is the same, the sequence is arithmetic.

Divide consecutive terms. If every ratio is the same, the sequence is geometric.

If neither test gives a constant, the sequence is neither.

Worked example

Classify each sequence. (a) 7, 3, −1, −5, … (b) 48, −24, 12, −6, … (c) 2, 6, 12, 20, …

  1. 01

    (a) Differences: 3−7=−43 - 7 = -4, −1−3=−4-1 - 3 = -4, −5−(−1)=−4-5 - (-1) = -4. The difference is always −4, so the sequence is arithmetic with d=−4d = -4. A decreasing arithmetic sequence simply adds a negative number.

  2. 02

    (b) Differences: −72, 36, −18. Not constant. Ratios: −24÷48=−1/2-24 \div 48 = -1/2, 12÷(−24)=−1/212 \div (-24) = -1/2, −6÷12=−1/2-6 \div 12 = -1/2. Geometric with r=−1/2r = -1/2. A negative ratio makes the terms switch sign every step.

  3. 03

    (c) Differences: 4, 6, 8. Ratios: 3, 2, 5/35/3. Neither test gives a constant, so the sequence is neither arithmetic nor geometric.

COMMON MISTAKE

“It's going down, so it must be arithmetic.”

The direction of change tells you nothing about the type. In the example above, 7, 3, −1, −5 decreases and is arithmetic, while 48, −24, 12, −6 shrinks toward 0 and is geometric. Always run both tests.

“Nova's differences 128, 192, 288 keep changing, so there is no pattern.”

Growing differences are exactly what a geometric sequence with r>1r > 1 produces. The pattern is in the ratios, not the differences.

06

Start From Any Term

The rules an=a0+dna_{n} = a_{0} + dn and gn=g0⋅rng_{n} = g_{0} \cdot r^{n} start counting at term 0. But you can start from any term you know. If you know the term aka_{k}, then getting to term nn takes (n−k)(n - k) steps:

an=ak+d (n−k)a_n = a_k + d\,(n - k) gn=gk⋅r n−kg_n = g_k \cdot r^{\,n-k}

CONCEPT

Why (n−k)(n - k)?

(n−k)(n - k) counts steps, not terms. From a3a_{3} to a8a_{8} there are 8−3=58 - 3 = 5 steps, so dd is added 5 times.

Check with Ridge: a3=2100a_{3} = 2100, so an=2100+300(n−3)=2100+300n−900=1200+300na_{n} = 2100 + 300(n - 3) = 2100 + 300n - 900 = 1200 + 300n. Same rule as before.

Check with Nova: g2=576g_{2} = 576, so gn=576(1.5)n−2g_{n} = 576(1.5)^{n-2}. Since 576÷1.52=256576 \div 1.5^{2} = 256, this is the same as 256(1.5)n256(1.5)^{n}.

COMMON MISTAKE

“Month 1 had 900 subscribers and the channel gains 150 per month, so an=900+150na_{n} = 900 + 150n.”

Here 900 is a1a_{1}, not a0a_{0}. With the anchor at k=1k = 1, the rule is an=900+150(n−1)a_{n} = 900 + 150(n - 1). Check n=4n = 4: the correct rule gives 900+150(3)=1,350900 + 150(3) = 1,350 (the list is 900, 1050, 1200, 1350), but the wrong rule gives 1,500, one step too many.

The familiar formula an=a1+d(n−1)a_{n} = a_{1} + d(n - 1) is just the k=1k = 1 case. Before writing any rule, check which index the first given term has, and subtract that index.

Quick check

An arithmetic sequence has a3=20a_3 = 20 and d=6d = 6. Using a3a_3 as the anchor, what is a10a_{10}?

07

Given Two Terms, Find the Rule

Two terms are enough to rebuild the whole sequence, because the gap between their indices tells you how many steps separate them.

Worked example

Example 1 (arithmetic). A sequence has a4=17a_{4} = 17 and a11=52a_{11} = 52. Find a rule for ana_{n} and find a20a_{20}.

  1. 01

    Steps between the terms: 11−4=711 - 4 = 7. Total change: 52−17=3552 - 17 = 35. Each step adds d=35÷7=5d = 35 \div 7 = 5.

  2. 02

    Anchor at a4a_{4}: an=17+5(n−4)a_{n} = 17 + 5(n - 4). (The same rule anchored at 0: a0=17−5⋅4=−3a_{0} = 17 - 5 \cdot 4 = -3, so an=−3+5na_{n} = -3 + 5n.)

  3. 03

    a20=17+5(20−4)=17+80=97a_{20} = 17 + 5(20 - 4) = 17 + 80 = 97.

Worked example

Example 2 (geometric, odd number of steps). A sequence has g2=250g_{2} = 250 and g5=16g_{5} = 16. Find a rule for gng_{n} and find g7g_{7}.

  1. 01

    From n=2n = 2 to n=5n = 5 is 3 steps, so rr is multiplied in 3 times: 250⋅r3=16250 \cdot r^{3} = 16, which gives r3=16/250=8/125r^{3} = 16/250 = 8/125.

  2. 02

    Take the cube root: r=2/5=0.4r = 2/5 = 0.4. An odd root of a real number has exactly one real answer, so this is the only possible ratio.

  3. 03

    gn=250(0.4)n−2g_{n} = 250(0.4)^{n-2}, so g7=250(0.4)5=2.56g_{7} = 250(0.4)^{5} = 2.56. (Starting from g5g_{5} instead: 16(0.4)2=2.5616(0.4)^{2} = 2.56. Same answer.)

Worked example

Example 3 (geometric, even number of steps). A sequence has g1=5g_{1} = 5 and g5=405g_{5} = 405. Find every possible rule, and find g4g_{4}.

  1. 01

    From n=1n = 1 to n=5n = 5 is 4 steps: 5⋅r4=4055 \cdot r^{4} = 405, so r4=81r^{4} = 81.

  2. 02

    An even power hides the sign: 34=813^{4} = 81 and (−3)4=81(-3)^{4} = 81. Both values of rr work, and nothing in the problem rules one out.

    r4=81⇒r=3orr=−3r^{4} = 81 \quad\Rightarrow\quad r = 3 \quad\text{or}\quad r = -3
  3. 03

    So two sequences fit. gn=5(3)n−1g_{n} = 5(3)^{n-1} gives 5, 15, 45, 135, 405, and gn=5(−3)n−1g_{n} = 5(-3)^{n-1} gives 5, −15, 45, −135, 405. Therefore g4=135g_{4} = 135 or g4=−135g_{4} = -135.

    Figure

    Both sequences pass through the two given terms. They agree at n=1n = 1, 3, 5 and have opposite signs at n=2n = 2 and n=4n = 4. (The dashed lines only guide the eye; a sequence has no values between the dots.)

    Some questions still have a single answer. For example, g7=5(±3)6=3,645g_{7} = 5( \pm 3)^{6} = 3,645 either way, because 6 multiplications by −3 contain an even number of negative signs.

COMMON MISTAKE

“r4=81r^{4} = 81, so r=3r = 3.”

Keeping only the positive root throws away a whole valid sequence. An even root (square root, 4th root, …) of a positive number always has two real answers, + and −. Write both, then reject one only when the problem gives a reason (see Section 8).

“r4=81r^{4} = 81, so r=81÷4=20.25r = 81 \div 4 = 20.25.”

The exponent 4 means multiplying rr by itself four times, not multiplying rr by 4. Check: 5⋅20.254≈840,7565 \cdot 20.25^{4} \approx 840,756, not 405.

Worked example

Try it yourself. (a) An arithmetic sequence has a6=−8a_{6} = -8 and a10=12a_{10} = 12. Find a25a_{25}. (b) A geometric sequence has g3=54g_{3} = 54 and g5=6g_{5} = 6. Find every possible value of g6g_{6}.

Answers: (a) d=20÷4=5d = 20 \div 4 = 5, so a25=−8+5(25−6)=87a_{25} = -8 + 5(25 - 6) = 87. (b) r2=6/54=1/9r^{2} = 6/54 = 1/9, so r=1/3r = 1/3 or r=−1/3r = -1/3. Then g6=6⋅(±1/3)=2g_{6} = 6 \cdot ( \pm 1/3) = 2 or −2.

Quick check

A geometric sequence has g1=6g_1 = 6 and g4=162g_4 = 162. What is the common ratio rr?

08

Back to Nova: Context Decides

REAL-LIFE EXAMPLE

Nova's Missing Records

Suppose the only surviving records say Nova had 576 subscribers at the end of month 2 and 2,916 at the end of month 6, and that the growth is geometric. What is the monthly ratio, and in which month does Nova first pass 10,000 subscribers?

  1. 01

    Month 2 to month 6 is 4 steps, an even number, so expect two candidates:

576 r4=2916⇒r4=5.0625⇒r=±1.5576\,r^{4} = 2916 \quad\Rightarrow\quad r^{4} = 5.0625 \quad\Rightarrow\quad r = \pm 1.5
  1. 02

    Both values satisfy the equation, but the context rules one out. With r=−1.5r = -1.5, month 3 would have 576(−1.5)=−864576(-1.5) = -864 subscribers. A subscriber count can't be negative, so r=1.5r = 1.5.

  1. 03

    Continue from g2=576g_{2} = 576: month 9 gives 576(1.5)7=9,841.5576(1.5)^{7} = 9,841.5 and month 10 gives 576(1.5)8=14,762.25576(1.5)^{8} = 14,762.25. Nova first passes 10,000 in month 10.

(A model can give decimals like 9,841.5; the real channel would have about 9,842.) In 2.13 you will solve 576(1.5)n−2=10,000576(1.5)^{n-2} = 10,000 directly with logarithms instead of building a table.

09

Practice

Worked example

P1. The terms 9, 14, 19, 24, … are labeled starting with a1=9a_{1} = 9. Write an explicit rule and find a40a_{40}.

Answer: d=5d = 5 and the anchor is a1a_{1}, so an=9+5(n−1)a_{n} = 9 + 5(n - 1). Then a40=9+5(39)=204a_{40} = 9 + 5(39) = 204.

Worked example

P2. The sequence 1000, 800, 640, … starts at g0g_{0}. Is it arithmetic or geometric? Find g6g_{6}.

Answer: The differences −200 and −160 are not equal, but the ratios are both 0.8. Geometric: gn=1000(0.8)ng_{n} = 1000(0.8)^{n}, so g6=262.144g_{6} = 262.144.

Worked example

P3. A geometric sequence has g2=−12g_{2} = -12 and g5=96g_{5} = 96. Find rr and g8g_{8}.

Answer: 3 steps, so r3=96÷(−12)=−8r^{3} = 96 \div (-12) = -8 and r=−2r = -2. A cube root has only one real answer, and it can be negative. Then g8=96(−2)3=−768g_{8} = 96(-2)^{3} = -768.

Common slips

  • “It's going down, so it must be arithmetic.”

    The direction of change tells you nothing about the type. In the example above, 7, 3, −1, −5 decreases and is arithmetic, while 48, −24, 12, −6 shrinks toward 0 and is geometric. Always run both tests.

    “Nova's differences 128, 192, 288 keep changing, so there is no pattern.”

    Growing differences are exactly what a geometric sequence with r>1r > 1 produces. The pattern is in the ratios, not the differences.

  • “Month 1 had 900 subscribers and the channel gains 150 per month, so an=900+150na_{n} = 900 + 150n.”

    Here 900 is a1a_{1}, not a0a_{0}. With the anchor at k=1k = 1, the rule is an=900+150(n−1)a_{n} = 900 + 150(n - 1). Check n=4n = 4: the correct rule gives 900+150(3)=1,350900 + 150(3) = 1,350 (the list is 900, 1050, 1200, 1350), but the wrong rule gives 1,500, one step too many.

    The familiar formula an=a1+d(n−1)a_{n} = a_{1} + d(n - 1) is just the k=1k = 1 case. Before writing any rule, check which index the first given term has, and subtract that index.

  • “r4=81r^{4} = 81, so r=3r = 3.”

    Keeping only the positive root throws away a whole valid sequence. An even root (square root, 4th root, …) of a positive number always has two real answers, + and −. Write both, then reject one only when the problem gives a reason (see Section 8).

    “r4=81r^{4} = 81, so r=81÷4=20.25r = 81 \div 4 = 20.25.”

    The exponent 4 means multiplying rr by itself four times, not multiplying rr by 4. Check: 5⋅20.254≈840,7565 \cdot 20.25^{4} \approx 840,756, not 405.

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3 cards · Sequences

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Recap card

6 lines to re-read the night before.

  1. 01

    A sequence is a function whose inputs are whole numbers, so its graph is separate dots.

  2. 02

    Arithmetic: constant difference dd. an=a0+dna_{n} = a_{0} + dn, or an=ak+d(n−k)a_{n} = a_{k} + d(n - k). Constant rate of change, like a linear function.

  3. 03

    Geometric: constant ratio rr. gn=g0⋅rng_{n} = g_{0} \cdot r^{n}, or gn=gk⋅rn−kg_{n} = g_{k} \cdot r^{n-k}. Constant proportional change.

  4. 04

    To classify, subtract consecutive terms (arithmetic test) and divide them (geometric test). Whether the terms go up or down does not decide the type.

  5. 05

    (n−k)(n - k) counts steps. From two terms: change ÷ steps gives dd; for rr, take the root that matches the number of steps. An even number of steps gives two candidates, rr and −r-r: keep both unless the context rules one out.

  6. 06

    Next, in 2.2: Ridge and Nova become functions of any real time tt, and we compare linear and exponential change directly.

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