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Topic 1.7A

Rational Functions and End Behavior

5 MIN READ7 IDEAS24 PROBLEMS14 flashcards

Read this first

30 sec

  1. 01

    "No horizontal asymptote" ≠ "no end behavior." The function still goes somewhere — it just isn't a flat line.

01

What Is a Rational Function?

A rational function is a ratio of two polynomials — one polynomial divided by another:

f(x)=p(x)q(x),q(x)≠0f(x) = \frac{p(x)}{q(x)}, \qquad q(x) \neq 0

Just like you can never divide by zero in arithmetic, a rational function is undefined wherever its denominator equals zero. Those excluded x-values are simply left out of the domain.

f(x)=2x+1x−3(x≠3)f(x) = \frac{2x + 1}{x - 3} \qquad (x \neq 3)

CONCEPT

Example

For f(x)=(2x+1)/(x−3)f(x) = (2x+1)/(x-3), the input x=3x = 3 would make the denominator 0 — so x=3x = 3 is excluded from the domain. Every other real number is allowed.

This note focuses on the function's end behavior — what happens to f(x)f(x) as x→±∞x \to \pm \infty — which depends on comparing the degree of the numerator to the degree of the denominator.

02

The Three End Behavior Cases

CONCEPT

Case 1: Numerator Degree < Denominator Degree

The bottom grows faster, so the fraction shrinks toward zero.

lim⁡x→±∞f(x)=0\lim_{x \to \pm\infty} f(x) = 0

CONCEPT

Case 2: Numerator Degree = Denominator Degree

Both grow at the same rate — the fraction settles at the ratio of leading coefficients.

lim⁡x→±∞f(x)=leading coeff of numleading coeff of denom\lim_{x \to \pm\infty} f(x) = \frac{\text{leading coeff of num}}{\text{leading coeff of denom}}

CONCEPT

Case 3: Numerator Degree > Denominator Degree

There is NO horizontal asymptote — but that does NOT mean end behavior doesn't exist!

The function still goes somewhere as x→±∞x \to \pm \infty — it just doesn't settle onto a flat horizontal line. Instead, it grows without bound (like a polynomial) or follows another curve entirely.

The simplest case (numerator exactly one degree higher) follows a slant line — see 1.7B. When the gap is two or more degrees, the end behavior follows a curve (parabola, cubic, etc.) instead of a line, found the same way: by long division.

KEY RULE

"No horizontal asymptote" ≠ "no end behavior." The function still goes somewhere — it just isn't a flat line.

−7.5 −5.0 −2.5 2.5 5.0 7.5 10.0 12.5 −8 −6 −4 −2 2 4 6 8 10 horizontal asymptote y = 2 vertical asymptote x = 3 f(x) = (2x+1)/(x−3): Horizontal Asymptote from Equal Degrees

f(x)=(2x+1)/(x−3)f(x) = (2x+1)/(x-3): equal degrees give a horizontal asymptote at the ratio of leading coefficients, y=2y = 2.

Quick check

What is the horizontal asymptote of g(x)=4−9x23x2+2xg(x) = \frac{4 - 9x^{2}}{3x^{2} + 2x}?

03

Real-Life Examples

REAL-LIFE EXAMPLE

Where This Shows Up

Mixing a solution: if you keep adding pure water to a fixed amount of salt, the concentration approaches — but never quite reaches — zero. This is a horizontal asymptote at y=0y = 0.

Average cost per unit: if a factory has a fixed setup cost plus a cost per item, average cost per item settles toward the per-item cost as production scales up hugely — a horizontal asymptote based on equal degrees.

04

Step-by-Step: Numerator Degree Less Than Denominator

Worked example

Find the horizontal asymptote of f(x)=(3x+2)/(x2+1)f(x) = (3x + 2) / (x^{2} + 1), using limit notation.

f(x)=3x+2x2+1f(x) = \frac{3x + 2}{x^2 + 1}
  1. 01

    Compare degrees: numerator has degree 1, denominator has degree 2.

  2. 02

    Since the numerator's degree is smaller, the horizontal asymptote is y=0y = 0:

    lim⁡x→±∞f(x)=0\lim_{x \to \pm\infty} f(x) = 0
  3. 03

    This makes sense: as xx grows huge, the x2x^{2} in the denominator overwhelms the xx in the numerator, shrinking the whole fraction toward 0.

    −10 −5 5 10 −1 1 2 3 horizontal asymptote y = 0 f(x) = (3x+2)/(x²+1): Numerator Degree < Denominator Degree

    f(x)=(3x+2)/(x2+1)f(x) = (3x+2)/(x^{2}+1) settles toward y=0y = 0 in both directions.

05

Step-by-Step: Equal Degrees

Worked example

Find the horizontal asymptote of f(x)=(2x+1)/(x−3)f(x) = (2x + 1) / (x - 3), using limit notation.

f(x)=2x+1x−3f(x) = \frac{2x + 1}{x - 3}
  1. 01

    Compare degrees: both numerator and denominator have degree 1 — they are equal.

  2. 02

    Take the ratio of the leading coefficients: 2 (from 2x) divided by 1 (from x):

    lim⁡x→±∞f(x)=21=2\lim_{x \to \pm\infty} f(x) = \frac{2}{1} = 2
  3. 03

    The horizontal asymptote is y=2y = 2.

COMMON MISTAKE

Don't confuse a horizontal asymptote with a value the function can never reach at any xx — a function can actually cross its horizontal asymptote for some x-values; the asymptote only describes far-away behavior.

Always fully compare degrees first — don't just look at the coefficients before checking which case you're in.

"No horizontal asymptote" does NOT mean "no end behavior." The function still has a definite end behavior in Case 3 — it just isn't a flat horizontal line.

Quick check

Can the graph of a rational function cross its horizontal asymptote?

06

Practice Problems

Worked example

Problem 1. Find the horizontal asymptote of f(x)=(5x2)/(2x2+3)f(x) = (5x^{2}) / (2x^{2} + 3).

f(x)=5x22x2+3f(x) = \frac{5x^2}{2x^2 + 3}
  1. 01

    Degrees are equal (both degree 2).

  2. 02

    Ratio of leading coefficients:

    lim⁡x→±∞f(x)=52\lim_{x \to \pm\infty} f(x) = \frac{5}{2}

Worked example

Problem 2. Find the horizontal asymptote of g(x)=4/(x+1)g(x) = 4 / (x + 1).

g(x)=4x+1g(x) = \frac{4}{x + 1}
  1. 01

    Numerator degree (0, since 4 is a constant) is less than denominator degree (1).

  2. 02

    Horizontal asymptote:

    lim⁡x→±∞g(x)=0\lim_{x \to \pm\infty} g(x) = 0

Common slips

  • Don't confuse a horizontal asymptote with a value the function can never reach at any xx — a function can actually cross its horizontal asymptote for some x-values; the asymptote only describes far-away behavior.

    Always fully compare degrees first — don't just look at the coefficients before checking which case you're in.

    "No horizontal asymptote" does not mean "no end behavior." The function still has a definite end behavior in Case 3 — it just isn't a flat horizontal line.

Lock it in

Try the flashcards

14 cards · Rational functions, Horizontal asymptote or end behavior?

Start

Recap card

5 lines to re-read the night before.

  1. 01

    Compare the degree of the numerator to the degree of the denominator to find horizontal asymptote behavior.

  2. 02

    Numerator < denominator → y=0y = 0.

  3. 03

    Equal degrees → y = ratio of leading coefficients.

  4. 04

    Numerator > denominator → no horizontal asymptote (see 1.7B).

  5. 05

    Limit notation — lim(x→±∞x \to \pm \infty) f(x)f(x) — is the formal way to state a rational function's end behavior.

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