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Topic 1.13

Function Model Selection and Assumption Articulation

10 MIN READ7 IDEAS23 PROBLEMS8 flashcards

Read this first

30 sec

  1. 01

    This restriction is a modeling assumption, not a mathematical fact about the equation. P(x)=−50x2+500x−800P(x) = -50x^{2}+500x-800 is perfectly well-defined for every real xx — the parabola keeps going in both directions. We are choosing to only trust the model where it matches reality (profit ≥ 0), and that choice is exactly what "assumption articulation" means: stating out loud which part of the math you're relying on, and why.

01

Selecting Models from Real Contexts

Look at the context, the data, or a graph, and select the function type that best models the situation. Remember: models often have a restricted domain and range once you bring real-world context into play.

Maya's Stickers

day123456
stickers101418222630

1st differences: 4, 4, 4, 4, 4 — constant → LINEAR

Theo's Followers

day123456
followers5915233345

1st: 4,6,8,10,12 (not constant). 2nd: 2,2,2,2 — constant → QUADRATIC

Priya's Views

day123456
views2103068130222

1st: 8,20,38,62,92. 2nd: 12,18,24,30. 3rd: 6,6,6 — constant → CUBIC

Owen's Savings — Watch the Spacing!

day124578
dollars505359626871

CONCEPT

Careful — the days aren't evenly spaced!

You can't just subtract consecutive values here, because the day-gaps aren't all the same size.

Instead, compute the RATE per day for each gap: (53−50)/(2−1)=3(53-50)/(2-1)=3, (59−53)/(4−2)=3(59-53)/(4-2)=3, (62−59)/(5−4)=3(62-59)/(5-4)=3, (68−62)/(7−5)=3(68-62)/(7-5)=3, (71−68)/(8−7)=3(71-68)/(8-7)=3.

Every rate is 3 — constant → LINEAR (slope 3), even though the days skip around.

02

Selecting a Model Type from Context Alone

Sometimes you won't have a data table at all — just a description of a situation. Here's how to pick a model type from the CONTEXT itself.

CONCEPT

Quick Criteria

Linear: roughly constant rate of change (steady growth/decline).

Quadratic: roughly LINEAR rate of change, OR roughly symmetric with a single max/min, OR context involving AREA.

Cubic: context involving VOLUME.

Rational: a quantity that's naturally a RATIO or DIVISION of two other quantities (like dose ÷ time, or cost ÷ units), OR a situation that LEVELS OFF near a fixed value instead of growing forever (concentration diluting toward 0, a rate approaching a saturation point).

Piecewise: the rule genuinely CHANGES at specific input values — different pricing tiers, distinct phases of a process (e.g., climbing, then cruising, then descending).

Worked example

(Calculator Active) A patient receives a dose of painkiller. The function p(t)=(4t2+12t)/(t3+3)p(t) = (4t^{2}+12t)/(t^{3}+3) models the amount in the bloodstream over time tt (hours). Which model TYPE is this, and how can you tell from the equation's structure alone?

  1. 01

    The right-hand side is one polynomial DIVIDED BY another polynomial — that structure itself signals a RATIONAL function, regardless of the specific numbers.

  2. 02

    This also matches the context clue: medicine amount typically rises then tapers off toward 0 as it's processed by the body — a leveling-off shape, not one that grows or falls forever like a polynomial would.

Worked example

For each situation, decide: linear, quadratic, or cubic model?

CONCEPT

a) Stacking cube-shaped storage boxes

Each box is a cube. Comparing the SIDE LENGTH to how much it can hold (VOLUME) → CUBIC (volume context).

CONCEPT

b) Buying movie tickets

Each ticket costs the same amount. Comparing number of tickets to total cost → LINEAR (constant rate per ticket).

CONCEPT

c) A circular pool cover

Comparing the pool's RADIUS to the AREA of material needed to cover it → QUADRATIC (area context).

03

Geometry Naturally Suggests a Degree

CONCEPT

Perimeter, Area, Volume

Perimeter — adding up side lengths → LINEAR in terms of a single side variable.

Area — multiplying two length dimensions together → QUADRATIC.

Volume — multiplying three length dimensions together → CUBIC.

This is a quick sanity check: if a problem describes a length-times-length-times-length quantity, expect a cubic model, even before you see any data.

Quick check

A can's height is always twice its radius rr. What type of function models its volume in terms of rr?

04

Restricted Domain and Range in Context

Worked example

A candle shop's weekly profit is P(x)=−50x2+500x−800P(x) = -50x^{2} + 500x - 800 dollars, where xx is the price charged per candle (in dollars). Find P(4)P(4) in context, the restricted domain, the restricted range, and the average rate of change on [5,7][5,7].

  1. 01

    P(4)P(4): plug in x=4x=4:

    P(4)=−50(16)+500(4)−800=400P(4) = -50(16) + 500(4) - 800 = 400
  2. 02

    In context: charging $4 per candle, the shop makes $400 profit that week.

  3. 03

    Restricted domain — profit can't realistically be negative, so find where P(x)=0P(x)=0:

    −50x2+500x−800=0  ⟹  x=2,  x=8-50x^{2} + 500x - 800 = 0 \implies x = 2,\; x = 8
  4. 04

    Restricted domain: [2,8][2, 8] dollars — charging less than $2 or more than $8 would lose money, which the shop wouldn't sustain.

KEY RULE

This restriction is a MODELING ASSUMPTION, not a mathematical fact about the equation. P(x)=−50x2+500x−800P(x) = -50x^{2}+500x-800 is perfectly well-defined for EVERY real xx — the parabola keeps going in both directions. We are CHOOSING to only trust the model where it matches reality (profit ≥ 0), and that choice is exactly what "assumption articulation" means: stating out loud which part of the math you're relying on, and why.

  1. 05

    Restricted range — the vertex (at x=5x=5) gives the maximum: P(5)=450P(5) = 450.

  1. 06

    Range: [0,450][0, 450] dollars.

  1. 07

    Average rate of change on [5,7][5,7]:

P(7)−P(5)7−5=250−4502=−100\frac{P(7) - P(5)}{7 - 5} = \frac{250 - 450}{2} = -100
  1. 08

    In context: raising the price from $5 to $7 DECREASES weekly profit at an average rate of $100 per dollar of price increase — you've priced past the sweet spot.

CONCEPT

Articulating the Assumption (the Other Half of This Topic's Name)

Whenever you restrict a domain or range "because it wouldn't make sense otherwise," you're making an assumption — the equation itself doesn't know or care about real-world limits.

Good practice: state the assumption explicitly, e.g. "We assume the shop only operates at prices where profit is non-negative," rather than treating [2,8][2,8] as if it fell out of the algebra alone.

Quick check

A box is cut from a 2020 cm by 3030 cm sheet with corner squares of side xx. What is the restricted domain of the volume model?

05

Piecewise Functions in Context

Worked example

The graph shows a regional flight's altitude over 35 minutes. Find the domain, range, and describe what happens on each piece.

0 5 10 15 20 25 30 35 minutes since takeoff 0 2000 4000 6000 8000 altitude (feet) climb +800 ft/min cruise constant descent −800 ft/min (10, 8000) (25, 8000) Three different rules, one flight — a piecewise model

  1. 01

    Domain in context: [0,35][0, 35] minutes — from takeoff to landing.

  2. 02

    Range in context: [0,8000][0, 8000] feet — from the ground up to cruising altitude.

  3. 03

    From t=0t=0 to 10: the plane climbs steadily (linear piece, rate +800 ft/min). From t=10t=10 to 25: it cruises at a constant 8000 ft. From t=25t=25 to 35: it descends steadily (linear piece, rate −800 ft/min).

COMMON MISTAKE

The domain and range "in context" should reflect the REAL-WORLD limits of the scenario, not just "all real numbers" — profit can't sustain being negative, a flight doesn't climb forever.

When x-values in a data table are unevenly spaced, always convert to a RATE (change ÷ time) before comparing — raw differences will mislead you.

06

Practice Problems

Worked example

Problem 1. Select linear, quadratic, or cubic, and justify with differences.

x123456
y64461016
  1. 01

    1st diffs: −2, 0, 2, 4, 6 — not constant.

  2. 02

    2nd diffs: 2, 2, 2, 2 — constant. Model: QUADRATIC.

Worked example

Problem 2 (Calculator Active). The strength of a radio signal (in relative units) at distance xx km from the tower is modeled by S(x)=5x/(x2+4)S(x) = 5x/(x^{2}+4). Find S(3)S(3), the AROC from x=2x=2 to x=3x=3, and the maximum signal strength.

  1. 01

    S(3)=15/13≈1.15S(3) = 15/13 \approx 1.15 — at 3 km from the tower, the signal strength is about 1.15 units.

  2. 02

    AROC[2,3] ≈ (1.15−1.25)/1≈−0.096(1.15 - 1.25)/1 \approx -0.096 — signal strength is DECREASING on average over this stretch.

  3. 03

    Using a graph or table (calculator active), the maximum is exactly 1.25, reached at x=2x=2 km — signal actually peaks a couple km out before fading, not right at the tower.

Worked example

Problem 3 (Calculator Active). A gardener has 40 m of fencing to enclose a rectangular garden against the side of a house (so only 3 sides need fencing). If xx is the width, A(x)=x(40−2x)A(x) = x(40-2x). Find the restricted domain, range, and the maximum area.

  1. 01

    Restricted domain: 0<x<200 < x < 20 (width must be positive, and the remaining length 40−2x40-2x must also stay positive).

  2. 02

    Restricted range: 0<A(x)≤2000 < A(x) \le 200 (area is always positive, capped at the maximum).

  3. 03

    Maximum area = 200 m², occurring at x=10x = 10 m (making a 10 m × 20 m rectangle).

  4. 04

    Note the assumption: 0 < x<20x < 20 comes from us DECIDING that a garden with zero or negative width/length isn't meaningful — the bare equation A(x)=x(40−2x)A(x)=x(40-2x) would happily accept any real xx.

Common slips

  • The domain and range "in context" should reflect the real-world limits of the scenario, not just "all real numbers" — profit can't sustain being negative, a flight doesn't climb forever.

    When x-values in a data table are unevenly spaced, always convert to a rate (change ÷ time) before comparing — raw differences will mislead you.

Lock it in

Try the flashcards

8 cards · Choosing a model

Start

Recap card

6 lines to re-read the night before.

  1. 01

    Finite differences determine polynomial degree — but convert to a rate first if x-values are unevenly spaced.

  2. 02

    Geometry gives a shortcut: perimeter↔linear, area↔quadratic, volume↔cubic.

  3. 03

    Ratios/division or a leveling-off shape suggest rational; a rule that changes at specific inputs suggests piecewise.

  4. 04

    Always restrict domain and range to what's physically possible in the real-world context, not just what the algebra allows.

  5. 05

    Assumption articulation: a restricted domain/range is a choice you make about the model, not a property of the equation itself — say so explicitly.

  6. 06

    Piecewise functions in context often model distinct phases of a real process — describe each piece's behavior separately.

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